Home Physics Simple Harmonic Motion (Oscillations) Energy The angular velocity and the amplitude of a …
Physics Simple Harmonic Motion (Oscillations) Energy MCQ (Single Correct)

The angular velocity and the amplitude of a simple pendulum is ꞷ and a respectively. At a displacement X from the mean position if its kinetic energy is T and potential energy is V, then the ratio of T to V is

A
X 2 ꞷ 2 / (a 2 – X 2 ꞷ 2 )
B
X 2 / (a 2 – X 2 )
C
(a 2 – X 2 ꞷ 2 ) / X 2 ꞷ 2
D
(a 2 – X 2 ) / X 2

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Text Solution

Verified by Experts
The correct answer is:
D

Kinetic energy T = m ω 2 (a 2 – x 2 )

and potential energy, V = m ω 2 x 2

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